Plane Figure Areas

Area of Plane Figures

Triangle

Triangle - equationzone.com

  • General formula (base and height):

    A=bh2A = \frac{b \cdot h}{2}

  • Heron’s Formula (sides):

    A=s(sa)(sb)(sc)A = \sqrt{s(s-a)(s-b)(s-c)}

    where s=a+b+c2s = \frac{a + b + c}{2} is the semiperimeter.

Acute Triangle

Acute Triangle - equationzone.com

Given two sides (aa, bb) and base cc:

A=c2a2(a2b2+c22c)2A = \frac{c}{2} \sqrt{a^2 - \left( \frac{a^2 - b^2 + c^2}{2c} \right)^2}

Obtuse Triangle

Obtuse Triangle - equationzone.com

Given two sides (aa, bb) and base cc:

A=c2b2(a2b2c22c)2A = \frac{c}{2} \sqrt{b^2 - \left( \frac{a^2 - b^2 - c^2}{2c} \right)^2}

Equilateral Triangle

Equilateral Triangle - equationzone.com

  • With side aa and height hh:

    A=ah2A = \frac{a \cdot h}{2}

    h=32ah = \frac{\sqrt{3}}{2} a

  • In terms of side aa:

    A=34a2A = \frac{\sqrt{3}}{4} a^2

  • In terms of height hh:

    A=33h2A = \frac{\sqrt{3}}{3} h^2

Equilateral Triangle - equationzone.com

  • In terms of the diameter dd of the circumscribed circle:

    A=3316d2A = \frac{3\sqrt{3}}{16} d^2

  • In terms of the radius rr of the inscribed circle:

    A=334r2A = \frac{3\sqrt{3}}{4} r^2

Square

Square - equationzone.com

  • In terms of side ll:

    A=l2A = l^2

    l=Al = \sqrt{A}

  • In terms of diagonal dd:

    d=l2d = l \cdot \sqrt{2}

    A=d22A = \frac{d^2}{2}

Square - equationzone.com

  • In terms of the radius rr of the inscribed circle:

    A=(2r)2=4r2A = (2r)^2 = 4r^2

Rectangle

Rectangle - equationzone.com

A=bhA = b \cdot h

d=b2+h2d = \sqrt{b^2 + h^2}

(where dd is the diagonal, bb the base and hh the height)

Parallelogram

Parallelogram - equationzone.com

  • Area:

    A=bh=absinαA = b \cdot h = a \cdot b \cdot \sin \alpha

  • Diagonals:

    d1=(a+hcotα)2+h2d_1 = \sqrt{(a + h \cot \alpha)^2 + h^2}

    d2=(ahcotα)2+h2d_2 = \sqrt{(a - h \cot \alpha)^2 + h^2}

Trapezoid / Trapezium

Trapezoid - equationzone.com

  • Area:

    A=(B+b)2h=mhA = \frac{(B + b)}{2} \cdot h = m \cdot h

    (where BB and bb are the bases, hh the height and mm the midline)

  • Midline:

    m=B+b2m = \frac{B + b}{2}

Trapezium / Irregular Quadrilateral

Trapezium - equationzone.com

Can be calculated by dividing it into triangles:

A=a(H+h)+dh+eH2A = \frac{a(H+h)+d \cdot h + e \cdot H}{2}

Regular Pentagon

Regular Pentagon - equationzone.com

  • In terms of the radius RR of the circumscribed circle:

    A=58R210+25A = \frac{5}{8} R^2 \cdot \sqrt{10 + 2\sqrt{5}}

    A=52R2sin72A = \frac{5}{2}R^2 \cdot \sin 72^\circ

  • In terms of side aa:

    A=145(5+25)a2A = \frac{1}{4} \sqrt{5(5+2\sqrt{5})} \cdot a^2

  • In terms of the apothem apa_{p}:

    A=5ap2525A = 5a_{p}^2 \cdot \sqrt{5 - 2\sqrt{5}}

    where the apothem is:

    ap=a21+25a_{p}= \frac{a}{2} \cdot \sqrt{1 + \frac{2}{\sqrt{5}}}

Regular Hexagon

Regular Hexagon - equationzone.com

Regular Hexagon - equationzone.com

  • In terms of side aa:

    A=332a2A = \frac{3\sqrt{3}}{2} a^2

  • In terms of the height between parallel sides hh:

    A=32h2A = \frac{\sqrt{3}}{2} h^2

  • In terms of the major diagonal dd:

    A=334d2A = \frac{3\sqrt{3}}{4} d^2

  • Important relations:
    The side aa is equal to the radius RR of the circumscribed circle: a=Ra = R.
    The height between parallel sides is: h=3ah = \sqrt{3} \cdot a.
    The major diagonal is: d=2ad = 2a.

Regular Octagon

Regular Octagon - equationzone.com

Regular Octagon - equationzone.com

  • Area in terms of side aa and apothem apa_{p}:

    A=Pap2=4aapA = \frac{P \cdot a_{p}}{2} = 4 \cdot a \cdot a_{p}

  • Perimeter:

    P=8aP = 8a

  • Apothem:

    ap=a2cotπ8a_{p} = \frac{a}{2} \cdot \cot \frac{\pi}{8}

  • Common approximate formulas:

    A=8a24tanπ84.828a2A = \frac{8a^2}{4\tan \frac{\pi}{8}} \approx 4.828 \cdot a^2

    A0.828s2A \approx 0.828 \cdot s^2

    (where ss is the width between parallel sides)

Irregular Polygon

Polygon - equationzone.com

Decomposed into triangles and their areas summed:

Atotal=A1+A2+A3+A_{\text{total}} = A_1 + A_2 + A_3 + \dots

Atotal=ah1+bh2+bh32A_{\text{total}} = \frac{a h_1 + b h_2 + b h_3 \dots}{2}


Area of the Circle and Sections of the Circle

Circle

Circle - equationzone.com

  • Area in terms of diameter dd:

    A=π4d2A = \frac{\pi}{4} d^2

  • Area in terms of radius rr:

    A=πr2A = \pi r^2

Quadrant and Concave Triangle

Quadrant and concave triangle - equationzone.com

  • Area of the quadrant:

    A=π16d2A = \frac{\pi}{16} d^2

    A=π4r2A = \frac{\pi}{4} r^2

  • Area of the concave triangle:

    A=(1π4)r2A' = \left(1 - \frac{\pi}{4}\right) r^2

(where rr is the radius and dd the diameter)

Circular Sector

Circular Sector - equationzone.com

  • Area (angle in degrees α\alpha^\circ):

    A=πr2α360A = \frac{\pi r^2 \alpha^\circ}{360^\circ}

  • Area (angle in radians θ\theta):

    A=θ2r2A = \frac{\theta}{2} r^2

  • Arc length LL:

    L=πrα180=θrL = \frac{\pi r \alpha^\circ}{180^\circ} = \theta \cdot r

Circular Segment

Circular Segment - equationzone.com
It is the area between a chord and its arc. Calculated by subtracting the area of the isosceles triangle formed by the radii and the chord from the area of the sector.

A=r22(θsinθ)A = \frac{r^2}{2} (\theta - \sin \theta)

(where θ\theta is in radians)

Annulus (Circular Ring)

Annulus - equationzone.com

  • Area in terms of diameter:

    A=π4(D2d2)A = \frac{\pi}{4} (D^2 - d^2)

  • Area in terms of radius:

    A=π(R2r2)A = \pi (R^2 - r^2)

(where RR and rr are the radii, DD and dd the diameters)

Annular Sector (Circular Trapezoid)

Annular sector - equationzone.com

  • Area (angle in degrees α\alpha^\circ):

    A=πα4360(D2d2)A = \frac{\pi \cdot \alpha^\circ}{4 \cdot 360^\circ} (D^2 - d^2)

    A=πα360(R2r2)A = \frac{\pi \alpha^\circ}{360^\circ} (R^2 - r^2)

  • Area (angle in radians θ\theta):

    A=θ8(D2d2)A = \frac{\theta}{8} (D^2 - d^2)

    A=θ2(R2r2)A = \frac{\theta}{2} (R^2 - r^2)